What is the integral of-tsqrt(z) ?

The integral of-tsqrt(z) is -(sqrt(z)t^2)/2+C

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integral of-tsqrt(z)

\int - t z d t

- \frac{z t ^{2}}{2} + C

Solution steps

\int - t z d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - z \cdot \int t d t

Apply the Power Rule

= - z \frac{t ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{z t ^{2}}{2}

Add a constant to the solution

= - \frac{z t ^{2}}{2} + C

What is the integral of-tsqrt(z) ?
The integral of-tsqrt(z) is -(sqrt(z)t^2)/2+C