What is the tangent of f(x)=x^4-5x^2+2,\at x=2 ?

The tangent of f(x)=x^4-5x^2+2,\at x=2 is y=12x-26

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tangent of f(x)=x^4-5x^2+2,\at x=2

tangent of

f (x) = x^{4} - 5 x^{2} + 2, at x = 2

y = 12 x - 26

Solution steps

Find the tangent point:

(2, - 2)

Find the slope of

f (x) = x^{4} - 5 x^{2} + 2 : \frac{df ( x )}{d x} = 4 x^{3} - 10 x

Compute the slope of

f (x) = x^{4} - 5 x^{2} + 2

x = 2 : m = 12

Find the line with slope m=

12

and passing through

(2, - 2) : y = 12 x - 26

y = 12 x - 26

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What is the tangent of f(x)=x^4-5x^2+2,\at x=2 ?
The tangent of f(x)=x^4-5x^2+2,\at x=2 is y=12x-26