What is the tangent of x^2+2xy-y^2+x=20,(3,4) ?

The tangent of x^2+2xy-y^2+x=20,(3,4) is y= 15/2 x-37/2

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tangent of x^2+2xy-y^2+x=20,(3,4)

tangent of

x^{2} + 2 x y - y^{2} + x = 20, (3, 4)

y = \frac{15}{2} x - \frac{37}{2}

Solution steps

Find the slope of

x^{2} + 2 x y - y^{2} + x = 20 : \frac{d y}{d x} = \frac{- 2 x - 1 - 2 y}{2 ( x - y )}

Compute the slope of

x^{2} + 2 x y - y^{2} + x = 20

(3, 4) : m = \frac{15}{2}

Find the line with slope m=

\frac{15}{2}

and passing through

(3, 4) : y = \frac{15}{2} x - \frac{37}{2}

y = \frac{15}{2} x - \frac{37}{2}

(3 x + 6)^{\frac{1}{5}}, at x = 2

\frac{\partial}{\partial x} (x^{2} y^{2} e^{4 x y})

\frac{d}{d x} ((x \cdot sinh (x) + cos (x))^{5})

\frac{d}{d x} (\frac{x + 6}{x ^{3} + x - 8})

x^{2} - 2 x - 1

What is the tangent of x^2+2xy-y^2+x=20,(3,4) ?
The tangent of x^2+2xy-y^2+x=20,(3,4) is y= 15/2 x-37/2