What is the derivative of x^2-2x-1 ?

The derivative of x^2-2x-1 is 2x-2

What is the first derivative of x^2-2x-1 ?

The first derivative of x^2-2x-1 is 2x-2

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derivative of

x^{2} - 2 x - 1

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x - 2 - 0

Simplify

= 2 x - 2

\frac{( s + 4 )}{s ^{2} + 4 s + 29}

\int 1

4 sec^{2} (x) - 6 sec^{4} (x)

y^{^{''}} + 1 y = x e^{5 x}

\frac{\partial}{\partial x} (x^{2} sin (x y + z))

What is the derivative of x^2-2x-1 ?
The derivative of x^2-2x-1 is 2x-2
What is the first derivative of x^2-2x-1 ?
The first derivative of x^2-2x-1 is 2x-2