What is the derivative of g(x)= 9/(x^3) ?

The derivative of g(x)= 9/(x^3) is -(27)/(x^4)

What is the first derivative of g(x)= 9/(x^3) ?

The first derivative of g(x)= 9/(x^3) is -(27)/(x^4)

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derivative of

g (x) = \frac{9}{x ^{3}}

- \frac{27}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 3 x^{- 3 - 1})

Simplify

9 (- 3 x^{- 3 - 1}) : - \frac{27}{x ^{4}}

= - \frac{27}{x ^{4}}

\frac{\partial}{\partial x} (x^{2} - 3 x y^{2})

\int \frac{25}{1 + 25 x ^{2}} d x

\frac{\partial}{\partial y} (x^{2} cos (y))

\int 3 x^{2} - 1 d x

y^{^{''}} - 2 y^{^{'}} - 8 y = 0

What is the derivative of g(x)= 9/(x^3) ?
The derivative of g(x)= 9/(x^3) is -(27)/(x^4)
What is the first derivative of g(x)= 9/(x^3) ?
The first derivative of g(x)= 9/(x^3) is -(27)/(x^4)