What is (\partial)/(\partial x)(x^2-3xy^2) ?

The answer to (\partial)/(\partial x)(x^2-3xy^2) is 2x-3y^2

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(\partial)/(\partial x)(x^2-3xy^2)

\frac{\partial}{\partial x} (x^{2} - 3 x y^{2})

2 x - 3 y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} - 3 x y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (3 x y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 x y^{2}) = 3 y^{2}

= 2 x - 3 y^{2}

\int \frac{25}{1 + 25 x ^{2}} d x

\frac{\partial}{\partial y} (x^{2} cos (y))

\int 3 x^{2} - 1 d x

y^{^{''}} - 2 y^{^{'}} - 8 y = 0

\frac{d}{d x} ((\frac{3}{2})^{x} ln (\frac{3}{2}))

What is (\partial)/(\partial x)(x^2-3xy^2) ?
The answer to (\partial)/(\partial x)(x^2-3xy^2) is 2x-3y^2