What is laplacetransform 2e^{-4t} ?

The answer to laplacetransform 2e^{-4t} is 2/(s+4)

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laplacetransform 2e^{-4t}

laplace transform

2 e^{- 4 t}

\frac{2}{s + 4}

Solution steps

L {2 e^{- 4 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {e^{- 4 t}}

L {e^{- 4 t}} : \frac{1}{s + 4}

= 2 \cdot \frac{1}{s + 4}

Refine

2 \frac{1}{s + 4} : \frac{2}{s + 4}

= \frac{2}{s + 4}

\frac{d}{d x} (ln (\frac{y}{x}))

\frac{\partial}{\partial y} (x^{2} - 2 x - x y)

\frac{x ^{2}}{( x ^{2} - 1 ) ^{4}}

\frac{\partial}{\partial y} (x^{2} e^{y})

(7) (- 1.6)

What is laplacetransform 2e^{-4t} ?
The answer to laplacetransform 2e^{-4t} is 2/(s+4)