What is (\partial)/(\partial y)(x^2-2x-xy) ?

The answer to (\partial)/(\partial y)(x^2-2x-xy) is -x

Popular >

(\partial)/(\partial y)(x^2-2x-xy)

\frac{\partial}{\partial y} (x^{2} - 2 x - x y)

- x

Solution steps

\frac{\partial}{\partial y} (x^{2} - 2 x - x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (x y) = x

= 0 - 0 - x

Simplify

= - x

\frac{x ^{2}}{( x ^{2} - 1 ) ^{4}}

\frac{\partial}{\partial y} (x^{2} e^{y})

(7) (- 1.6)

x^{2} y^{^{'}} + 2 x y = 11 cos^{2} (x)

y = lo g_{5} (7 x + 1)

What is (\partial)/(\partial y)(x^2-2x-xy) ?
The answer to (\partial)/(\partial y)(x^2-2x-xy) is -x