What is the integral of x^3sec^2(y) ?

The integral of x^3sec^2(y) is x^3tan(y)+C

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integral of x^3sec^2(y)

\int x^{3} sec^{2} (y) d y

x^{3} tan (y) + C

Solution steps

\int x^{3} sec^{2} (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x^{3} \cdot \int sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= x^{3} tan (y)

Add a constant to the solution

= x^{3} tan (y) + C

y^{^{''}} + \frac{y ^{^{'}}}{x} = 2 x + 1

arctan (x)

y^{^{''}} - 7 y^{^{'}} + 3 y = x e^{x}

x \to 0 lim (\frac{5 x ^{2} - 4 x}{x})

k = 1 \sum \infty \frac{k !}{10 1 ^{k}}

What is the integral of x^3sec^2(y) ?
The integral of x^3sec^2(y) is x^3tan(y)+C