What is the limit as x approaches 0 of (5x^2-4x)/x ?

The limit as x approaches 0 of (5x^2-4x)/x is -4

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limit as x approaches 0 of (5x^2-4x)/x

x \to 0 lim (\frac{5 x ^{2} - 4 x}{x})

- 4

Solution steps

x \to 0 lim (\frac{5 x ^{2} - 4 x}{x})

Simplify

\frac{5 x ^{2} - 4 x}{x} : 5 x - 4

= x \to 0 lim (5 x - 4)

Plug in the value

x = 0

= 5 \cdot 0 - 4

Simplify

= - 4

k = 1 \sum \infty \frac{k !}{10 1 ^{k}}

f (x) = 4 x^{2} - 5 x

\int (\frac{( x + 1 ) ^{2}}{x}) d x

\frac{\partial}{\partial x} (9 x^{2} - 11 x y^{2})

What is the limit as x approaches 0 of (5x^2-4x)/x ?
The limit as x approaches 0 of (5x^2-4x)/x is -4