What is the limit as x approaches 3 of (x^2-9)/(x-3) ?

The limit as x approaches 3 of (x^2-9)/(x-3) is 6

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limit as x approaches 3 of (x^2-9)/(x-3)

x \to 3 lim (\frac{x ^{2} - 9}{x - 3})

6

Solution steps

x \to 3 lim (\frac{x ^{2} - 9}{x - 3})

Simplify

\frac{x ^{2} - 9}{x - 3} : x + 3

= x \to 3 lim (x + 3)

Plug in the value

x = 3

= 3 + 3

Simplify

= 6

d er i v a t i v e f (x) = \frac{( x ^{2} - 2 x - 48 )}{x + 6}

\int \frac{cos ( x )}{3 cos ( x ) - 5} d x

t an g e n t 3 sin (x), at x = \frac{π}{4}

y^{^{'}} + 3 x^{7} y^{9} + \frac{y}{x} = 0

x y^{^{'}} - 2 y = - x

What is the limit as x approaches 3 of (x^2-9)/(x-3) ?
The limit as x approaches 3 of (x^2-9)/(x-3) is 6