What is the derivative of f(x)=((x^2-2x-48))/(x+6) ?

The derivative of f(x)=((x^2-2x-48))/(x+6) is 1

What is the first derivative of f(x)=((x^2-2x-48))/(x+6) ?

The first derivative of f(x)=((x^2-2x-48))/(x+6) is 1

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derivative of

f (x) = \frac{( x ^{2} - 2 x - 48 )}{x + 6}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 2 x - 48}{x + 6})

Simplify

\frac{x ^{2} - 2 x - 48}{x + 6} : x - 8

= \frac{d}{d x} (x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (8)

\frac{d x}{d x} = 1

\frac{d}{d x} (8) = 0

= 1 - 0

Simplify

= 1

\int \frac{cos ( x )}{3 cos ( x ) - 5} d x

t an g e n t 3 sin (x), at x = \frac{π}{4}

y^{^{'}} + 3 x^{7} y^{9} + \frac{y}{x} = 0

x y^{^{'}} - 2 y = - x

d er i v a t i v e \frac{x + 1}{x}

What is the derivative of f(x)=((x^2-2x-48))/(x+6) ?
The derivative of f(x)=((x^2-2x-48))/(x+6) is 1
What is the first derivative of f(x)=((x^2-2x-48))/(x+6) ?
The first derivative of f(x)=((x^2-2x-48))/(x+6) is 1