What is the tangent of f(x)=14cos(x),\at x=7 ?

The tangent of f(x)=14cos(x),\at x=7 is y=-14sin(7)x+14cos(7)+98sin(7)

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tangent of f(x)=14cos(x),\at x=7

tangent of

f (x) = 14 cos (x), at x = 7

y = - 14 sin (7) x + 14 cos (7) + 98 sin (7)

Solution steps

Find the tangent point:

(7, 14 cos (7))

Find the slope of

f (x) = 14 cos (x) : \frac{df ( x )}{d x} = - 14 sin (x)

Compute the slope of

f (x) = 14 cos (x)

x = 7 : m = - 14 sin (7)

Find the line with slope m=

- 14 sin (7)

and passing through

(7, 14 cos (7)) : y = - 14 sin (7) x + 14 cos (7) + 98 sin (7)

y = - 14 sin (7) x + 14 cos (7) + 98 sin (7)

y^{^{'}} + ln (x) = \frac{y}{x}

\int_{0}^{1} 1 + (- \frac{1}{x})^{2} d x

\frac{( 6 )}{s ^{2} + 5 s + 6}

\int_{1}^{R} x e^{- 4 x} d x

\frac{d y}{d x} = (y - 7)^{2}

What is the tangent of f(x)=14cos(x),\at x=7 ?
The tangent of f(x)=14cos(x),\at x=7 is y=-14sin(7)x+14cos(7)+98sin(7)