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Popular >

y^'+ln(x)= y/x

Solution

y^{^{'}} + ln (x) = \frac{y}{x}

Solution

y = - \frac{x ln ^{2} ( x )}{2} + c_{1} x

Solution steps

y^{'} (x) + ln (x) = \frac{y}{x}

Solve linear ODE:

y = - \frac{x ln ^{2} ( x )}{2} + c_{1} x

y = - \frac{x ln ^{2} ( x )}{2} + c_{1} x

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Frequently Asked Questions (FAQ)

What is the solution for y^'+ln(x)= y/x ?
The solution for y^'+ln(x)= y/x is y=-(xln^2(x))/2+c_{1}x