What is the derivative of f(x)= 3/(x+1) ?

The derivative of f(x)= 3/(x+1) is -3/((x+1)^2)

What is the first derivative of f(x)= 3/(x+1) ?

The first derivative of f(x)= 3/(x+1) is -3/((x+1)^2)

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derivative of

f (x) = \frac{3}{x + 1}

- \frac{3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 3 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

3 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : - \frac{3}{( x + 1 ) ^{2}}

= - \frac{3}{( x + 1 ) ^{2}}

x \to 0 lim (2 x + e^{x})

\int - 10 e^{c o s (x)} sin (x) d x

f^{^{'}} (x) = 2 x

\int cos^{2} (\frac{4 - x}{3}) d x

\frac{d}{d t} (\frac{1}{2} t)

What is the derivative of f(x)= 3/(x+1) ?
The derivative of f(x)= 3/(x+1) is -3/((x+1)^2)
What is the first derivative of f(x)= 3/(x+1) ?
The first derivative of f(x)= 3/(x+1) is -3/((x+1)^2)