What is the integral of-cos(2t) ?

The integral of-cos(2t) is -1/2 sin(2t)+C

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integral of-cos(2t)

\int - cos (2 t) d t

- \frac{1}{2} sin (2 t) + C

Solution steps

\int - cos (2 t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int cos (2 t) d t

Apply u-substitution

: \int cos (u) \frac{1}{2} d u

= - \int cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - \frac{1}{2} sin (u)

Substitute back

u = 2 t

= - \frac{1}{2} sin (2 t)

Add a constant to the solution

= - \frac{1}{2} sin (2 t) + C

\int \frac{1}{( 1 - x ) ( 2 - x )} d x

\frac{1}{cos ^{2} ( x )}

\frac{d x}{d t} = x

\frac{\partial}{\partial y} (2 x - y)

x \to \infty lim \frac{( ( lo g _{2} ( x ) ) ^{2} )}{x}