What is (\partial)/(\partial y)(2x-y) ?

The answer to (\partial)/(\partial y)(2x-y) is -1

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(\partial)/(\partial y)(2x-y)

\frac{\partial}{\partial y} (2 x - y)

- 1

Solution steps

\frac{\partial}{\partial y} (2 x - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

x \to \infty lim \frac{( ( lo g _{2} ( x ) ) ^{2} )}{x}

x y y^{^{'}} = x^{6} + 3 y^{2}

\int 3 x sin (x) cos (x) d x

\frac{d}{d x} (ln (x \cdot x^{2} - 1))

f (x) = x^{9} cos (x)

What is (\partial)/(\partial y)(2x-y) ?
The answer to (\partial)/(\partial y)(2x-y) is -1