What is the integral of sqrt(1+cos(t)) ?

The integral of sqrt(1+cos(t)) is 2sqrt(2)tan(t/2)cos(t/2)+C

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integral of sqrt(1+cos(t))

\int 1 + cos (t) d t

22 tan (\frac{t}{2}) cos (\frac{t}{2}) + C

Solution steps

\int 1 + cos (t) d t

Apply u-substitution

: \int \frac{2 2}{( 1 + u ^{2} ) 1 + u ^{2}} d u

= \int \frac{2 2}{( 1 + u ^{2} ) 1 + u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 22 \cdot \int \frac{1}{( 1 + u ^{2} ) 1 + u ^{2}} d u

Simplify

(1 + u^{2}) 1 + u^{2} : (1 + u^{2})^{\frac{3}{2}}

= 22 \cdot \int \frac{1}{( 1 + u ^{2} ) ^{\frac{3}{2}}} d u

Apply Trigonometric Substitution

: \int cos (v) d v

= 22 \cdot \int cos (v) d v

Use the common integral:

\int cos (v) d v = sin (v)

= 22 sin (v)

Substitute back

= 22 sin (arctan (tan (\frac{t}{2})))

Simplify

22 sin (arctan (tan (\frac{t}{2}))) : 22 tan (\frac{t}{2}) cos (\frac{t}{2})

= 22 tan (\frac{t}{2}) cos (\frac{t}{2})

Add a constant to the solution

= 22 tan (\frac{t}{2}) cos (\frac{t}{2}) + C

\frac{1}{s ^{2} + 12 s + 100}

\int_{0}^{1} 1 + 12 x d x

x \to 7 lim (3)

\int (4 x + 2) e^{2 x} d x

x \to 0 lim (ln (6 x + 1))

What is the integral of sqrt(1+cos(t)) ?
The integral of sqrt(1+cos(t)) is 2sqrt(2)tan(t/2)cos(t/2)+C