What is the solution for x^2+5y(dy)/(dx)=0 ?

The solution for x^2+5y(dy)/(dx)=0 is y=sqrt(-(2x^3)/(15)+c_{1)},y=-sqrt(-(2x^3)/(15)+c_{1)}

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x^2+5y(dy)/(dx)=0

x^{2} + 5 y \frac{d y}{d x} = 0

y = - \frac{2 x ^{3}}{15} + c_{1}, y = - - \frac{2 x ^{3}}{15} + c_{1}

Solution steps

x^{2} + 5 y \frac{d y}{d x} = 0

Solve separable ODE:

y = - \frac{2 x ^{3}}{15} + c_{1}, y = - - \frac{2 x ^{3}}{15} + c_{1}

y = - \frac{2 x ^{3}}{15} + c_{1}, y = - - \frac{2 x ^{3}}{15} + c_{1}

x \to - 1 lim ((9 x + 1)^{2})

\int 2 x y e^{x^{2}} d x

\int \frac{1}{x ( ln ( x ^{4} ) ) ^{6}} d x

x \to 0 lim (\frac{sin ( 4 x )}{9})

\frac{d}{d x} (\frac{1}{2 x + 5})

What is the solution for x^2+5y(dy)/(dx)=0 ?
The solution for x^2+5y(dy)/(dx)=0 is y=sqrt(-(2x^3)/(15)+c_{1)},y=-sqrt(-(2x^3)/(15)+c_{1)}