What is the tangent of (sqrt(x))/(6x-4),\at x=9 ?

The tangent of (sqrt(x))/(6x-4),\at x=9 is y=-29/7500 x+237/2500

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tangent of (sqrt(x))/(6x-4),\at x=9

tangent of

\frac{x}{6 x - 4}, at x = 9

y = - \frac{29}{7500} x + \frac{237}{2500}

Solution steps

Find the tangent point:

(9, \frac{3}{50})

Find the slope of

y = \frac{x}{6 x - 4} : \frac{d y}{d x} = \frac{- 3 x - 2}{x ( 6 x - 4 ) ^{2}}

Compute the slope of

y = \frac{x}{6 x - 4}

x = 9 : m = - \frac{29}{7500}

Find the line with slope m=

- \frac{29}{7500}

and passing through

(9, \frac{3}{50}) : y = - \frac{29}{7500} x + \frac{237}{2500}

y = - \frac{29}{7500} x + \frac{237}{2500}

\frac{\partial}{\partial x} (2 x^{4} y z^{3})

x \to 0 - lim (\frac{6}{5 x ^{\frac{1}{3}}})

\int (5 x^{2} - 2 x + 3) d x

What is the tangent of (sqrt(x))/(6x-4),\at x=9 ?
The tangent of (sqrt(x))/(6x-4),\at x=9 is y=-29/7500 x+237/2500