What is the derivative of-8/(\sqrt[4]{x)} ?

The derivative of-8/(\sqrt[4]{x)} is 2/(x^{5/4)}

What is the first derivative of-8/(\sqrt[4]{x)} ?

The first derivative of-8/(\sqrt[4]{x)} is 2/(x^{5/4)}

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derivative of

\frac{2}{x ^{\frac{5}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 8 \frac{d}{d x} (x^{- \frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 8 (- \frac{1}{4} x^{- \frac{1}{4} - 1})

Simplify

- 8 (- \frac{1}{4} x^{- \frac{1}{4} - 1}) : \frac{2}{x ^{\frac{5}{4}}}

= \frac{2}{x ^{\frac{5}{4}}}

x \to \infty lim (5 x + \frac{1}{x})

\frac{\partial}{\partial x} (t^{2} + 4 x^{3})

\int - \frac{1}{3} cos (3 x) d x

\int \frac{2 x ^{2}}{3 - 4 x ^{3}} d x

- 2

What is the derivative of-8/(\sqrt[4]{x)} ?
The derivative of-8/(\sqrt[4]{x)} is 2/(x^{5/4)}
What is the first derivative of-8/(\sqrt[4]{x)} ?
The first derivative of-8/(\sqrt[4]{x)} is 2/(x^{5/4)}