integral of (4x+5)

Lösung

\int (4 x + 5) d x

2 x^{2} + 5 x + C

Schritte zur Lösung

\int 4 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x + \int 5 d x

\int 4 x d x = 2 x^{2}

\int 5 d x = 5 x

= 2 x^{2} + 5 x

Füge eine Konstante zur Lösung hinzu

= 2 x^{2} + 5 x + C

\int 3 4 x - 7 d x

\int_{0}^{2} 2 π x (3 x (x - 2)^{2}) d x

n = 1 \sum \infty \frac{2 n}{3 n - 1}

\frac{d}{d x} (\frac{3 a}{4 x ^{5}})

\frac{\partial}{\partial y} (x^{6 y})