What is the derivative of y=ln(8-3x) ?

The derivative of y=ln(8-3x) is -3/(8-3x)

What is the first derivative of y=ln(8-3x) ?

The first derivative of y=ln(8-3x) is -3/(8-3x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = ln (8 - 3 x)

- \frac{3}{8 - 3 x}

Solution steps

\frac{d}{d x} (ln (8 - 3 x))

Apply the chain rule:

\frac{1}{8 - 3 x} \frac{d}{d x} (8 - 3 x)

= \frac{1}{8 - 3 x} \frac{d}{d x} (8 - 3 x)

\frac{d}{d x} (8 - 3 x) = - 3

= \frac{1}{8 - 3 x} (- 3)

Simplify

\frac{1}{8 - 3 x} (- 3) : - \frac{3}{8 - 3 x}

= - \frac{3}{8 - 3 x}

\int e^{- u} u d u

x sin (\frac{8}{x})

\frac{d}{d x} (\frac{1 - x}{( 1 + x ) ^{3}})

\int \frac{2 x + 5}{( x - 4 ) ( x + 1 )} d x

y = 3 x^{3}

What is the derivative of y=ln(8-3x) ?
The derivative of y=ln(8-3x) is -3/(8-3x)
What is the first derivative of y=ln(8-3x) ?
The first derivative of y=ln(8-3x) is -3/(8-3x)