What is the derivative of y=3x^3 ?

The derivative of y=3x^3 is 9x^2

What is the first derivative of y=3x^3 ?

The first derivative of y=3x^3 is 9x^2

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derivative of

y = 3 x^{3}

9 x^{2}

Solution steps

\frac{d}{d x} (3 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot 3 x^{3 - 1}

Simplify

= 9 x^{2}

y^{^{''}} + 3 y^{^{'}} + 2 y = sin (t)

\int (3 - 2 x) sin (5 x) d x

\int cot (9 x) d x

y = x^{5} \cdot e^{x}

\frac{d}{d x} (2 (3^{- x})^{2} + lo g_{2} (x^{4} - 1))