What is the derivative of x^4-9x+6 ?

The derivative of x^4-9x+6 is 4x^3-9

What is the first derivative of x^4-9x+6 ?

The first derivative of x^4-9x+6 is 4x^3-9

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\frac{d}{d x} (x^{4} - 9 x + 6)

4 x^{3} - 9

Solution steps

\frac{d}{d x} (x^{4} - 9 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (6) = 0

= 4 x^{3} - 9 + 0

Simplify

= 4 x^{3} - 9

\frac{d}{d x} (a tan (x))

\int \frac{t ^{2}}{a ^{4} + t ^{2}} d t

\int (\frac{5}{x ^{2}}) d x

f (x) = (x^{2} - 4) \cdot (x + 4)

\frac{d}{d x} (\frac{5 x}{6})

What is the derivative of x^4-9x+6 ?
The derivative of x^4-9x+6 is 4x^3-9
What is the first derivative of x^4-9x+6 ?
The first derivative of x^4-9x+6 is 4x^3-9