What is the integral of (5/(x^2)) ?

The integral of (5/(x^2)) is -5/x+C

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integral of (5/(x^2))

\int (\frac{5}{x ^{2}}) d x

- \frac{5}{x} + C

Solution steps

\int \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= 5 (- \frac{1}{x})

Simplify

5 (- \frac{1}{x}) : - \frac{5}{x}

= - \frac{5}{x}

Add a constant to the solution

= - \frac{5}{x} + C

f (x) = (x^{2} - 4) \cdot (x + 4)

\frac{d}{d x} (\frac{5 x}{6})

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f (x) = \frac{2}{6 + 8 x}

\frac{\partial}{\partial u} (2 u)