What is the limit as x approaches 0+of e^{sqrt(x)} ?

The limit as x approaches 0+of e^{sqrt(x)} is 1

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limit as x approaches 0+of e^{sqrt(x)}

x \to 0 + lim (e^{x})

1

Solution steps

x \to 0 + lim (e^{x})

Plug in the value

x = 0

= e^{0}

Simplify

= 1

\frac{d}{d x} (ln (cos (e^{x^{2} - s e c (x)})))

\int \frac{9 e ^{- \frac{1}{x}}}{x ^{2}} d x

f (x) = x^{2} + 1, at x = 2

x^{4} - 4 x^{2} + 10, at x = 1

What is the limit as x approaches 0+of e^{sqrt(x)} ?
The limit as x approaches 0+of e^{sqrt(x)} is 1