What is the integral of sin^3(7/3)x ?

The integral of sin^3(7/3)x is (sin^3(7/3)x^2)/2+C

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integral of sin^3(7/3)x

\int sin^{3} (\frac{7}{3}) x d x

\frac{sin ^{3} ( \frac{7}{3} ) x ^{2}}{2} + C

Solution steps

\int sin^{3} (\frac{7}{3}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{3} (\frac{7}{3}) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin^{3} (\frac{7}{3}) \frac{x ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ^{3} ( \frac{7}{3} ) x ^{2}}{2}

Add a constant to the solution

= \frac{sin ^{3} ( \frac{7}{3} ) x ^{2}}{2} + C

\int \frac{5}{9 - x ^{2}} d x

y^{^{''}} + 25 y = cos (5 x) + sin (5 x)

n = 1 \sum \infty \frac{7}{3 ^{n - 1}}

\int \frac{1}{x ^{2} + 49} d x

x^{3}, 3 x^{2} - 4

What is the integral of sin^3(7/3)x ?
The integral of sin^3(7/3)x is (sin^3(7/3)x^2)/2+C