What is (\partial)/(\partial y)(3x^2y^2-2) ?

The answer to (\partial)/(\partial y)(3x^2y^2-2) is 6x^2y

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(\partial)/(\partial y)(3x^2y^2-2)

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 2)

6 x^{2} y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y^{2} - 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2} y^{2}) - \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (3 x^{2} y^{2}) = 6 x^{2} y

\frac{\partial}{\partial y} (2) = 0

= 6 x^{2} y - 0

Simplify

= 6 x^{2} y

n = 1 \sum \infty \frac{1}{( 2 n + 1 ) ^{2}}

n = 1 \sum \infty \frac{4 n + 1}{4 ^{n + 1}}

\frac{d}{d x} (e^{(- x^{2})})

\int sin^{3} (\frac{7}{3}) x d x

\int \frac{5}{9 - x ^{2}} d x

What is (\partial)/(\partial y)(3x^2y^2-2) ?
The answer to (\partial)/(\partial y)(3x^2y^2-2) is 6x^2y