What is area f(x)=x^3-6x^2+8,g(x)=x^2-4x ?

The answer to area f(x)=x^3-6x^2+8,g(x)=x^2-4x is 84.13262…

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area f(x)=x^3-6x^2+8,g(x)=x^2-4x

area

f (x) = x^{3} - 6 x^{2} + 8, g (x) = x^{2} - 4 x

84.13262 \dots

Solution steps

Apply the area formula:

\int_{- 0.78871 \dots}^{6.13554 \dots} x^{3} - 6 x^{2} + 8 - (x^{2} - 4 x) d x

Solve

\int_{- 0.78871 \dots}^{6.13554 \dots} x^{3} - 6 x^{2} + 8 - (x^{2} - 4 x) d x : 84.13262 \dots

The area is:

= 84.13262 \dots

\frac{d y}{d x} = (x - 8) e^{- 2 y}

f (x) = 2 x + 6

2 x^{2} + x y + y^{2} = 4

f (x) = \frac{x ^{2} - 4 x + 3}{x + 1}

\int \frac{1}{1 - tan ( 6 x )} d x

What is area f(x)=x^3-6x^2+8,g(x)=x^2-4x ?
The answer to area f(x)=x^3-6x^2+8,g(x)=x^2-4x is 84.13262…