What is the integral of xsin(x)+1 ?

The integral of xsin(x)+1 is -xcos(x)+sin(x)+x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of xsin(x)+1

\int x sin (x) + 1 d x

- x cos (x) + sin (x) + x + C

Solution steps

\int x sin (x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x sin (x) d x + \int 1 d x

\int x sin (x) d x = - x cos (x) + sin (x)

\int 1 d x = x

= - x cos (x) + sin (x) + x

Add a constant to the solution

= - x cos (x) + sin (x) + x + C

\int_{2}^{4} (x - 2) d x

d er i v a t i v e cos (6 x)

\frac{\partial}{\partial z} (z x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + 2 x y)

\int y^{4} d y

What is the integral of xsin(x)+1 ?
The integral of xsin(x)+1 is -xcos(x)+sin(x)+x+C