y^'e^{9x}=0

Lösung

y^{^{'}} e^{9 x} = 0

y = c_{1}

Schritte zur Lösung

y^{'} (x) e^{9 x} = 0

Isoliere

y^{'} (x) : y^{'} (x) = 0

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 0 d x

\int 0 d x = c_{1}

y = c_{1}

\int \frac{x ^{2}}{( x + 2 ) ^{6}} d x

x \to 3 lim (2 x^{2} + 3 x - 1)

t \to 0 lim (\frac{1 - cos ( 3 t )}{t})

\int \frac{1}{( x ^{2} + y ^{2} ) ^{3}} d y

\int cos (t^{3}) d t