What is (\partial)/(\partial x)(3x^4y^2-2) ?

The answer to (\partial)/(\partial x)(3x^4y^2-2) is 12x^3y^2

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(\partial)/(\partial x)(3x^4y^2-2)

\frac{\partial}{\partial x} (3 x^{4} y^{2} - 2)

12 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{4} y^{2} - 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{4} y^{2}) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (3 x^{4} y^{2}) = 12 y^{2} x^{3}

\frac{\partial}{\partial x} (2) = 0

= 12 y^{2} x^{3} - 0

Simplify

= 12 x^{3} y^{2}

n = 1 \sum \infty \frac{1}{( n ) ( n + 8 )}

x \to 4 lim (\frac{y}{x})

\int (9 x + 4)^{2} d x

\int_{1}^{\infty} x e^{x} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{x}

What is (\partial)/(\partial x)(3x^4y^2-2) ?
The answer to (\partial)/(\partial x)(3x^4y^2-2) is 12x^3y^2