What is the sum from n=1 to infinity of 1/((n)(n+8)) ?

The sum from n=1 to infinity of 1/((n)(n+8)) is converges

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sum from n=1 to infinity of 1/((n)(n+8))

n = 1 \sum \infty \frac{1}{( n ) ( n + 8 )}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ( n + 8 )}

Apply Series Comparison Test:

converges

= converges

x \to 4 lim (\frac{y}{x})

\int (9 x + 4)^{2} d x

\int_{1}^{\infty} x e^{x} d x

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{x}

x \to 2 lim (825)

What is the sum from n=1 to infinity of 1/((n)(n+8)) ?
The sum from n=1 to infinity of 1/((n)(n+8)) is converges