What is the derivative of f(x)=2x+7 ?

The derivative of f(x)=2x+7 is 2

What is the first derivative of f(x)=2x+7 ?

The first derivative of f(x)=2x+7 is 2

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derivative of

f (x) = 2 x + 7

2

Solution steps

\frac{d}{d x} (2 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (7)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (7) = 0

= 2 + 0

Simplify

= 2

(x + y) d x - (x + y - 2) d y = 0

\frac{d}{d x} ((x^{2} - 1) (x^{2} + 1))

\int t sec^{2} (2 t) d t

\frac{\partial}{\partial y} (\frac{y}{( x + y ) ^{2}})

\frac{\partial}{\partial x} (e^{- 2 t} cos (π x))

What is the derivative of f(x)=2x+7 ?
The derivative of f(x)=2x+7 is 2
What is the first derivative of f(x)=2x+7 ?
The first derivative of f(x)=2x+7 is 2