What is the tangent of y= 6/(sqrt(x)),(16, 6/4) ?

The tangent of y= 6/(sqrt(x)),(16, 6/4) is y=-3/64 x+9/4

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tangent of y= 6/(sqrt(x)),(16, 6/4)

tangent of

y = \frac{6}{x}, (16, \frac{6}{4})

y = - \frac{3}{64} x + \frac{9}{4}

Solution steps

Find the slope of

y = \frac{6}{x} : \frac{d y}{d x} = - \frac{3}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{6}{x}

(16, \frac{6}{4}) : m = - \frac{3}{64}

Find the line with slope m=

- \frac{3}{64}

and passing through

(16, \frac{6}{4}) : y = - \frac{3}{64} x + \frac{9}{4}

y = - \frac{3}{64} x + \frac{9}{4}

y = 2 sin (x) cos (x)

\int 2 tan^{2} (x) + tan^{4} (x) d x

\int \frac{x}{3 x + 1} d x

\int \frac{tan ( θ )}{sec ( θ )} d θ

\int x cos (πn x) d x

What is the tangent of y= 6/(sqrt(x)),(16, 6/4) ?
The tangent of y= 6/(sqrt(x)),(16, 6/4) is y=-3/64 x+9/4