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Popular Calculus >

integral of xcos(pinx)

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Solution

∫xcos(πnx)dx

Solution

π2n21​(πnxsin(πnx)+cos(πnx))+C
Solution steps
∫xcos(πnx)dx
Apply u-substitution
=∫π2n2ucos(u)​du
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=π2n21​⋅∫ucos(u)du
Apply Integration By Parts
=π2n21​(usin(u)−∫sin(u)du)
∫sin(u)du=−cos(u)
=π2n21​(usin(u)−(−cos(u)))
Substitute back u=nxπ=π2n21​(nxπsin(nxπ)−(−cos(nxπ)))
Simplify=π2n21​(πnxsin(πnx)+cos(πnx))
Add a constant to the solution=π2n21​(πnxsin(πnx)+cos(πnx))+C

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Frequently Asked Questions (FAQ)

  • What is the integral of xcos(pinx) ?

    The integral of xcos(pinx) is 1/(pi^2n^2)(pinxsin(pinx)+cos(pinx))+C
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