What is the derivative of (sqrt(x)/(2x-7)) ?

The derivative of (sqrt(x)/(2x-7)) is (-2x-7)/(2sqrt(x)(2x-7)^2)

What is the first derivative of (sqrt(x)/(2x-7)) ?

The first derivative of (sqrt(x)/(2x-7)) is (-2x-7)/(2sqrt(x)(2x-7)^2)

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\frac{d}{d x} (\frac{x}{2 x - 7})

\frac{- 2 x - 7}{2 x ( 2 x - 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{2 x - 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( 2 x - 7 ) - \frac{d}{d x} ( 2 x - 7 ) x}{( 2 x - 7 ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (2 x - 7) = 2

= \frac{\frac{1}{2 x} ( 2 x - 7 ) - 2 x}{( 2 x - 7 ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( 2 x - 7 ) - 2 x}{( 2 x - 7 ) ^{2}} : \frac{- 2 x - 7}{2 x ( 2 x - 7 ) ^{2}}

= \frac{- 2 x - 7}{2 x ( 2 x - 7 ) ^{2}}

\int_{9}^{25} \frac{x - 9}{x} d x

(cos (x) + y sin (x)) d x + (cos (x)) d y = 0

\frac{\partial}{\partial x} (6 x y e^{- x^{2} - y^{2}})

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What is the derivative of (sqrt(x)/(2x-7)) ?
The derivative of (sqrt(x)/(2x-7)) is (-2x-7)/(2sqrt(x)(2x-7)^2)
What is the first derivative of (sqrt(x)/(2x-7)) ?
The first derivative of (sqrt(x)/(2x-7)) is (-2x-7)/(2sqrt(x)(2x-7)^2)