What is the tangent of y=6sec(x),\at x= pi/6 ?

The tangent of y=6sec(x),\at x= pi/6 is y=4x+4sqrt(3)-(2pi)/3

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tangent of y=6sec(x),\at x= pi/6

tangent of

y = 6 sec (x), at x = \frac{π}{6}

y = 4 x + 43 - \frac{2 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{6}, 43)

Find the slope of

y = 6 sec (x) : \frac{d y}{d x} = 6 sec (x) tan (x)

Compute the slope of

y = 6 sec (x)

x = \frac{π}{6} : m = 4

Find the line with slope m=

4

and passing through

(\frac{π}{6}, 43) : y = 4 x + 43 - \frac{2 π}{3}

y = 4 x + 43 - \frac{2 π}{3}

\int cos^{4} (d) x d x

x^{2} y^{^{''}} + 3 x y^{^{'}} + 3 y = 0

\frac{\partial}{\partial t} (4 t)

f (x) = 3 x + 8

n = 0 \sum \infty ln (\frac{1}{3 ^{n}})

What is the tangent of y=6sec(x),\at x= pi/6 ?
The tangent of y=6sec(x),\at x= pi/6 is y=4x+4sqrt(3)-(2pi)/3