What is the solution for (dy)/(dx)=x^2(1+y^2) ?

The solution for (dy)/(dx)=x^2(1+y^2) is y=tan((x^3)/3+c_{1})

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(dy)/(dx)=x^2(1+y^2)

\frac{d y}{d x} = x^{2} (1 + y^{2})

y = tan (\frac{x ^{3}}{3} + c_{1})

Solution steps

\frac{d y}{d x} = x^{2} (1 + y^{2})

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + c_{1})

y = tan (\frac{x ^{3}}{3} + c_{1})

\int \frac{x ^{3}}{x ^{2} - 16} d x

x \to \infty lim (4 x^{4})

\frac{d y}{d x} = tan (x + y)

\frac{d}{d x} (3 (0)^{2} - 3)

x \to 1 - lim (- \frac{1}{x - 2})

What is the solution for (dy)/(dx)=x^2(1+y^2) ?
The solution for (dy)/(dx)=x^2(1+y^2) is y=tan((x^3)/3+c_{1})