What is the solution for (dy)/(dx)=tan(x+y) ?

The solution for (dy)/(dx)=tan(x+y) is y=arcsin(e^{x+c_{1}})+2pin-x,y=pi+arcsin(-e^{x+c_{1}})+2pin-x

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(dy)/(dx)=tan(x+y)

\frac{d y}{d x} = tan (x + y)

y = arcsin (e^{x + c_{1}}) + 2 πn - x, y = π + arcsin (- e^{x + c_{1}}) + 2 πn - x

Solution steps

\frac{d y}{d x} = tan (x + y)

Solve using substitution:

y = arcsin (e^{x + c_{1}}) + 2 πn - x, y = π + arcsin (- e^{x + c_{1}}) + 2 πn - x

y = arcsin (e^{x + c_{1}}) + 2 πn - x, y = π + arcsin (- e^{x + c_{1}}) + 2 πn - x

\frac{d}{d x} (3 (0)^{2} - 3)

x \to 1 - lim (- \frac{1}{x - 2})

\frac{1}{( s - 1 ) ( s )}

\frac{d}{d x} (\frac{1 - 2 x}{x ^{2}})

2 x^{2} - 12 x + 11

What is the solution for (dy)/(dx)=tan(x+y) ?
The solution for (dy)/(dx)=tan(x+y) is y=arcsin(e^{x+c_{1}})+2pin-x,y=pi+arcsin(-e^{x+c_{1}})+2pin-x