What is the tangent of y=5sqrt(x),\at x=4,x=9 ?

The tangent of y=5sqrt(x),\at x=4,x=9 is y= 5/4 x+5

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tangent of y=5sqrt(x),\at x=4,x=9

tangent of

y = 5 x, at x = 4, x = 9

y = \frac{5}{4} x + 5

Solution steps

Find the tangent point:

(4, 10)

Find the slope of

y = 5 x : \frac{d y}{d x} = \frac{5}{2 x}

Compute the slope of

y = 5 x

x = 4 : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, 10) : y = \frac{5}{4} x + 5

y = \frac{5}{4} x + 5

\int_{1}^{3} x e^{- x} d x

\int sec^{2} (2 t) d t

\frac{\partial}{\partial z} (x + yz)

t \to \infty lim (e^{2 t})

\int_{0}^{8} 3 t^{2} - 36 t + 105 d t

What is the tangent of y=5sqrt(x),\at x=4,x=9 ?
The tangent of y=5sqrt(x),\at x=4,x=9 is y= 5/4 x+5