What is the integral from 1 to 3 of xe^{-x} ?

The integral from 1 to 3 of xe^{-x} is -4/(e^3)+2/e

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integral from 1 to 3 of xe^{-x}

\int_{1}^{3} x e^{- x} d x

- \frac{4}{e ^{3}} + \frac{2}{e}

Solution steps

\int_{1}^{3} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{1}^{3}

= [- e^{- x} x - \int - e^{- x} d x]_{1}^{3}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{1}^{3}

Compute the boundaries:

- \frac{4}{e ^{3}} + \frac{2}{e}

= - \frac{4}{e ^{3}} + \frac{2}{e}

\int sec^{2} (2 t) d t

\frac{\partial}{\partial z} (x + yz)

t \to \infty lim (e^{2 t})

\int_{0}^{8} 3 t^{2} - 36 t + 105 d t

x \to 1 lim (g (x))

What is the integral from 1 to 3 of xe^{-x} ?
The integral from 1 to 3 of xe^{-x} is -4/(e^3)+2/e