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Popular >

y^'=y(1-y),y(0)=6

Solution

y^{^{'}} = y (1 - y), y (0) = 6

Solution

y = - \frac{6 e ^{t}}{5 - 6 e ^{t}}

Solution steps

y^{'} (t) = y (1 - y)

Solve separable ODE:

y = - \frac{6 e ^{t}}{5 - 6 e ^{t}}

y = - \frac{6 e ^{t}}{5 - 6 e ^{t}}

Popular Examples

y^'=sqrt(1-y^2)sin(x)

y^{^{'}} = 1 - y^{2} sin (x)

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x \to 0 + lim (\frac{x e ^{\frac{1}{x}}}{2})

integral of 9xsin^2(x)

\int 9 x sin^{2} (x) d x

integral of ((2x-3))/((x^2+2x-3)^{3/2)}

\int \frac{( 2 x - 3 )}{( x ^{2} + 2 x - 3 ) ^{\frac{3}{2}}} d x

limit as x approaches 2 of [|-x/2 |]+x^2

x \to 2 lim ([- \frac{x}{2}] + x^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'=y(1-y),y(0)=6 ?
The solution for y^'=y(1-y),y(0)=6 is y=-(6e^t)/(5-6e^t)