What is the solution for y^'=sqrt(1-y^2)sin(x) ?

The solution for y^'=sqrt(1-y^2)sin(x) is y=sin(-cos(x)+c_{1})

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y^'=sqrt(1-y^2)sin(x)

y^{^{'}} = 1 - y^{2} sin (x)

y = sin (- cos (x) + c_{1})

Solution steps

y^{'} (x) = 1 - y^{2} sin (x)

Solve separable ODE:

y = sin (- cos (x) + c_{1})

y = sin (- cos (x) + c_{1})

x \to 0 + lim (\frac{x e ^{\frac{1}{x}}}{2})

\int 9 x sin^{2} (x) d x

\int \frac{( 2 x - 3 )}{( x ^{2} + 2 x - 3 ) ^{\frac{3}{2}}} d x

x \to 2 lim ([- \frac{x}{2}] + x^{2})

\frac{\partial}{\partial y} (3 sin (x) sin (y))

What is the solution for y^'=sqrt(1-y^2)sin(x) ?
The solution for y^'=sqrt(1-y^2)sin(x) is y=sin(-cos(x)+c_{1})