What is the limit as x approaches+3 of 5/(x^2-9) ?

The limit as x approaches+3 of 5/(x^2-9) is diverges

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limit as x approaches+3 of 5/(x^2-9)

x \to + 3 lim (\frac{5}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{5}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{5}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{5}{x ^{2} - 9}) = - \infty

= diverges

\frac{d y}{d t} = 20 - \frac{y}{230 + 16 t}

\frac{d y}{d x} = e^{x} - 6 x^{2}

y = x^{3} + x

\int x^{2} e x d x

\frac{sin ( θ )}{3} + \frac{c}{θ}

What is the limit as x approaches+3 of 5/(x^2-9) ?
The limit as x approaches+3 of 5/(x^2-9) is diverges