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Popular >

(\partial)/(\partial x)(1+x^2+y^2)

Solution

\frac{\partial}{\partial x} (1 + x^{2} + y^{2})

Solution

2 x

Solution steps

\frac{\partial}{\partial x} (1 + x^{2} + y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 + 2 x + 0

Simplify

= 2 x

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n = 1 \sum \infty \frac{1}{n} + \frac{1}{n ^{2}}

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\int \frac{x ^{2} + 4}{x} d x

Frequently Asked Questions (FAQ)

What is (\partial)/(\partial x)(1+x^2+y^2) ?
The answer to (\partial)/(\partial x)(1+x^2+y^2) is 2x