What is the integral of (x^2+4)/x ?

The integral of (x^2+4)/x is (x^2)/2+4ln|x|+C

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integral of (x^2+4)/x

\int \frac{x ^{2} + 4}{x} d x

\frac{x ^{2}}{2} + 4 ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{2} + 4}{x} d x

Expand

\frac{x ^{2} + 4}{x} : x + \frac{4}{x}

= \int x + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{4}{x} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{4}{x} d x = 4 ln ∣ x ∣

= \frac{x ^{2}}{2} + 4 ln ∣ x ∣

Add a constant to the solution

= \frac{x ^{2}}{2} + 4 ln ∣ x ∣ + C

x \to \infty lim (ln (x))

\int \frac{1}{x 12 x + 49} d x

\int \frac{1}{( 324 + x ^{2} ) ^{\frac{3}{2}}} d x

2 tan^{2} (2 x)

\frac{d}{d t} (ln (t^{2} + 1))

What is the integral of (x^2+4)/x ?
The integral of (x^2+4)/x is (x^2)/2+4ln|x|+C