What is the derivative of (x^3-2)^2 ?

The derivative of (x^3-2)^2 is 6x^2(x^3-2)

What is the first derivative of (x^3-2)^2 ?

The first derivative of (x^3-2)^2 is 6x^2(x^3-2)

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derivative of

(x^{3} - 2)^{2}

6 x^{2} (x^{3} - 2)

Solution steps

\frac{d}{d x} ((x^{3} - 2)^{2})

Apply the chain rule:

2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

= 2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

\frac{d}{d x} (x^{3} - 2) = 3 x^{2}

= 2 (x^{3} - 2) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} - 2)

\frac{d}{d x} (x - 6 x)

x \to 1 lim (x^{3})

x \to + 3 lim (\frac{5}{x ^{2} - 9})

\frac{d y}{d t} = 20 - \frac{y}{230 + 16 t}

\frac{d y}{d x} = e^{x} - 6 x^{2}

What is the derivative of (x^3-2)^2 ?
The derivative of (x^3-2)^2 is 6x^2(x^3-2)
What is the first derivative of (x^3-2)^2 ?
The first derivative of (x^3-2)^2 is 6x^2(x^3-2)