What is the integral of x^9e^{x^{10}} ?

The integral of x^9e^{x^{10}} is 1/10 e^{x^{10}}+C

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integral of x^9e^{x^{10}}

\int x^{9} e^{x^{10}} d x

\frac{1}{10} e^{x^{10}} + C

Solution steps

\int x^{9} e^{x^{10}} d x

Apply u-substitution

: \int \frac{e ^{u^{\frac{10}{9}}} u ^{\frac{1}{9}}}{9} d u

= \int \frac{e ^{u^{\frac{10}{9}}} u ^{\frac{1}{9}}}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int e^{u^{\frac{10}{9}}} u^{\frac{1}{9}} d u

Apply u-substitution

: \int \frac{9 e ^{v}}{10} d v

= \frac{1}{9} \cdot \int \frac{9 e ^{v}}{10} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \frac{9}{10} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= \frac{1}{9} \cdot \frac{9}{10} e^{v}

Substitute back

= \frac{1}{9} \cdot \frac{9}{10} e^{(x^{9})^{\frac{10}{9}}}

Simplify

\frac{1}{9} \cdot \frac{9}{10} e^{(x^{9})^{\frac{10}{9}}} : \frac{1}{10} e^{x^{10}}

= \frac{1}{10} e^{x^{10}}

Add a constant to the solution

= \frac{1}{10} e^{x^{10}} + C

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What is the integral of x^9e^{x^{10}} ?
The integral of x^9e^{x^{10}} is 1/10 e^{x^{10}}+C